If Current Of 10a Flows 4 Minutes, Find The Quantity Of Electricity Transferred

If current of 10A flows 4 minutes, find the quantity of electricity transferred

Hello!

If current of 10A flows 4 minutes, find the quantity of electricity transferred

We have the following data:

i (current intensity) = 10 A (or 10 C/s)

Q (Amount of charge electrified) = ? (in Coulomb)

Δt (time interval) = 4 minutes = 4 * (60s) => t = 240 seconds

Formula:

$i = \dfrac{Q}{\Delta{T}} \to \boxed{Q = i * \Delta{T}}$

Solving:

$Q = i * \Delta{T}$

$Q = 10\:\frac{C}{\diagup\!\!\!\!\!s} * 2400\:\diagup\!\!\!\!\!s$

$\boxed{\boxed{Q = 24000\:C}}\end{array}}\qquad\checkmark$

Answer:

The quantity of electricity transferred is 24000 Coulom

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I Hope this helps, greetings ... Dexteright02! =)

Kyokyarni